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P1 2025 May Q3

A Level / Edexcel / P1

IAL 2025 May Paper · Question 3

题目

Problem

Find

∫(x+3)23x dx,\begin{align*} \int \frac{(x+3)^2}{3\sqrt{x}}\,\mathrm{d}x, \end{align*}

writing your answer in simplest form.

(5)
题目中文翻译

求

∫(x+3)23x dx,\begin{align*} \int \frac{(x+3)^2}{3\sqrt{x}}\,\mathrm{d}x, \end{align*}

并将答案化为最简形式。

解答

解法一

思路

展开

先展开分子,再逐项除以 3x3\sqrt{x}。化成幂函数后就可以逐项积分。

答题过程

展开

Expand the numerator:

(x+3)2=x2+6x+9.\begin{align*} (x+3)^2=x^2+6x+9. \end{align*}

Then

(x+3)23x= x2+6x+93x1/2= 13x3/2+2x1/2+3x−1/2.\begin{align*} \frac{(x+3)^2}{3\sqrt{x}} =&\,\frac{x^2+6x+9}{3x^{1/2}}\\ =&\,\frac13x^{3/2}+2x^{1/2}+3x^{-1/2}. \end{align*}

So

∫(x+3)23x dx= ∫(13x3/2+2x1/2+3x−1/2) dx= 13⋅x5/25/2+2⋅x3/23/2+3⋅x1/21/2+c= 215x5/2+43x3/2+6x1/2+c.\begin{align*} \int \frac{(x+3)^2}{3\sqrt{x}}\,\mathrm{d}x =&\,\int\left( \frac13x^{3/2}+2x^{1/2}+3x^{-1/2} \right)\,\mathrm{d}x\\ =&\,\frac13\cdot\frac{x^{5/2}}{5/2} +2\cdot\frac{x^{3/2}}{3/2} +3\cdot\frac{x^{1/2}}{1/2}+c\\ =&\,\frac{2}{15}x^{5/2} +\frac43x^{3/2} +6x^{1/2}+c. \end{align*}