Skip to content
CalcGospel 國際數學圖譜
返回

IAL 2023 May Q1

A Level / Edexcel / P2

IAL 2023 May Paper · Question 1

题目

Problem

The continuous curve CC has equation y=f(x)y = f(x).

A table of values of xx and yy for y=f(x)y = f(x) is shown below.

xx4.04.04.24.24.44.44.64.64.84.85.05.0
yy9.29.28.45568.45563.85123.85125.03425.03427.82977.82978.68.6

Use the trapezium rule with all the values of yy in the table to find an approximation for

45f(x)dx\int_4^5 f(x)\,\mathrm{d}x

giving your answer to 3 decimal places.

(3)
题目中文翻译

连续曲线 CC 的方程为 y=f(x)y = f(x)

下表给出了 y=f(x)y = f(x)xxyy 值。

xx4.04.04.24.24.44.44.64.64.84.85.05.0
yy9.29.28.45568.45563.85123.85125.03425.03427.82977.82978.68.6

用梯形法则,使用表中所有 yy 值,求 45f(x)dx\displaystyle\int_4^5 f(x)\,\mathrm{d}x 的近似值,答案保留3位小数。

(3分)

解答

解法一

思路

梯形法则公式:abf(x)dxh2[y0+2(y1+y2++yn1)+yn]\int_a^b f(x)\,\mathrm{d}x \approx \dfrac{h}{2}\big[y_0 + 2(y_1 + y_2 + \cdots + y_{n-1}) + y_n\big],其中 hh 是步长,nn 是区间数。

答题过程

From the table, the step size is h=0.2h = 0.2 and n=6n = 6 intervals.

\int_4^5 f(x)\,\mathrm{d}x \approx&\, \frac{0.2}{2}\Big[y_0 + 2(y_1 + y_2 + y_3 + y_4 + y_5) + y_6\Big] \\[4mm] =&\, 0.1\Big[9.2 + 2(8.4556 + 3.8512 + 5.0342 + 7.8297) + 8.6\Big] \\[4mm] =&\, 0.1\Big[9.2 + 2(25.1707) + 8.6\Big] \\[4mm] =&\, 0.1\Big[9.2 + 50.3414 + 8.6\Big] \\[4mm] =&\, 0.1 \times 68.1414 \\[4mm] =&\, 6.452 \end{align*}$$ $$\boxed{6.452}$$