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P2 2025 May Q10

A Level / Edexcel / P2

IAL 2025 May Paper · Question 10

题目

Problem

In this question you must show detailed reasoning.

Use algebra to prove by exhaustion that,

for all positive integers mm that are not multiples of 33, the value of

m2+3m+2m^2+3m+2

is always a multiple of 33

(4)
题目中文翻译

本题必须展示详细的推理过程。

用代数方法,通过穷举证明:对于所有不是 33 的倍数的正整数 mm,

m2+3m+2m^2+3m+2

的值总是 33 的倍数。(4分)

解答

解法一

思路

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mm 不是 33 的倍数,所以除以 33 的余数只能是 11 或 22。因此只需检查 m=3p+1m=3p+1 和 m=3p+2m=3p+2 两类。

答题过程

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Since mm is a positive integer that is not a multiple of 33, there are two cases:

m=3p+1orm=3p+2,m=3p+1 \quad\text{or}\quad m=3p+2,

where pp is a non-negative integer.

Case 1: m=3p+1m=3p+1.

m2+3m+2= (3p+1)2+3(3p+1)+2= 9p2+6p+1 +9p+3+2= 9p2+15p+6= 3(3p2+5p+2).\begin{align*} m^2+3m+2 =&\,(3p+1)^2+3(3p+1)+2\\ =&\,9p^2+6p+1\\ &\,\hspace{2pt}+9p+3+2\\ =&\,9p^2+15p+6\\ =&\,3(3p^2+5p+2). \end{align*}

So m2+3m+2m^2+3m+2 is a multiple of 33 in this case.

Case 2: m=3p+2m=3p+2.

m2+3m+2= (3p+2)2+3(3p+2)+2= 9p2+12p+4 +9p+6+2= 9p2+21p+12= 3(3p2+7p+4).\begin{align*} m^2+3m+2 =&\,(3p+2)^2+3(3p+2)+2\\ =&\,9p^2+12p+4\\ &\,\hspace{2pt}+9p+6+2\\ =&\,9p^2+21p+12\\ =&\,3(3p^2+7p+4). \end{align*}

So m2+3m+2m^2+3m+2 is also a multiple of 33 in this case.

Therefore, for all positive integers mm that are not multiples of 33, m2+3m+2m^2+3m+2 is always a multiple of 33.

解法二

思路

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先因式分解:m2+3m+2=(m+1)(m+2)m^2+3m+2=(m+1)(m+2)。如果 mm 不是 33 的倍数,那么接下来的两个整数 m+1,m+2m+1,m+2 之中必有一个是 33 的倍数。

答题过程

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Factorise:

m2+3m+2=(m+1)(m+2).\begin{align*} m^2+3m+2=(m+1)(m+2). \end{align*}

Since mm is a positive integer not divisible by 33, m=3p+1m=3p+1 or m=3p+2m=3p+2, where pp is a non-negative integer.

If m=3p+1m=3p+1, then

m+2=3p+3=3(p+1),\begin{align*} m+2=3p+3=3(p+1), \end{align*}

so m+2m+2 is a multiple of 33.

If m=3p+2m=3p+2, then

m+1=3p+3=3(p+1),\begin{align*} m+1=3p+3=3(p+1), \end{align*}

so m+1m+1 is a multiple of 33.

In both cases, one factor of

(m+1)(m+2)\begin{align*} (m+1)(m+2) \end{align*}

is a multiple of 33.

Therefore,

m2+3m+2\begin{align*} m^2+3m+2 \end{align*}

is always a multiple of 33.