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IAL 2022 Oct Q4

A Level / Edexcel / P3

IAL 2022 Oct Paper · Question 4

题目

Problem

y=log10(2x+1)y=\log_{10}(2x+1)

(a) Express xx in terms of yy.

(2)

(b) Hence, giving your answer in terms of xx, find

dydx\frac{dy}{dx}
(3)
题目中文翻译 y=log10(2x+1)y=\log_{10}(2x+1)

(a) 用 yy 表示 xx

(b) 由此用 xx 表示并求

dydx\frac{dy}{dx}

解答

(a)

We have

y=log10(2x+1)y=\log_{10}(2x+1)

Rewrite this in exponential form:

10y=2x+110^y=2x+1

So

2x=10y12x=10^y-1

Therefore

x=10y12\boxed{x=\frac{10^y-1}{2}}

(b)

From part (a),

x=10y12x=\frac{10^y-1}{2}

Differentiate both sides with respect to yy:

dxdy=1210yln10\frac{dx}{dy} =\frac12\cdot 10^y\ln10

So

dxdy=10yln102\frac{dx}{dy} =\frac{10^y\ln10}{2}

Therefore

dydx=110yln102\frac{dy}{dx} =\frac{1}{\frac{10^y\ln10}{2}}

Thus

dydx=210yln10\frac{dy}{dx} =\frac{2}{10^y\ln10}

Since

10y=2x+110^y=2x+1

we get

dydx=2(2x+1)ln10\boxed{\frac{dy}{dx}=\frac{2}{(2x+1)\ln10}}