题目
Problem
y=log10(2x+1)
(a) Express x in terms of y.
(2)
(b) Hence, giving your answer in terms of x, find
dxdy
(3)
题目中文翻译
y=log10(2x+1)
(a) 用 y 表示 x。
(b) 由此用 x 表示并求
dxdy
解答
(a)
We have
y=log10(2x+1)
Rewrite this in exponential form:
10y=2x+1
So
2x=10y−1
Therefore
x=210y−1
(b)
From part (a),
x=210y−1
Differentiate both sides with respect to y:
dydx=21⋅10yln10
So
dydx=210yln10
Therefore
dxdy=210yln101
Thus
dxdy=10yln102
Since
10y=2x+1
we get
dxdy=(2x+1)ln102