Skip to content
CalcGospel 國際數學圖譜
返回

P4 2024 Jan Q8

A Level / Edexcel / P4

IAL 2024 Jan Paper · Question 8

题目

Problem

Use proof by contradiction to prove that the curve with equation

y=2x+x3+cos⁡xy=2x+x^3+\cos x

has no stationary points.

(4)
题目中文翻译

用反证法证明方程

y=2x+x3+cos⁡xy=2x+x^3+\cos x

所表示的曲线没有驻点。

(4)

解答

解法一

思路

展开

按反证法,先假设曲线存在驻点,因此在某个实数 xx 处导数为 00。求导并整理后,会得到 sin⁡x=3x2+2\sin x=3x^2+2;但右边至少为 22,与正弦函数的值域矛盾。

答题过程

展开

Assume, for a contradiction, that the curve has a stationary point for some real value of xx. Then

dydx=0.\frac{\mathrm{d}y}{\mathrm{d}x}=0.

Differentiating,

dydx=2+3x2−sin⁡x.\frac{\mathrm{d}y}{\mathrm{d}x} =2+3x^2-\sin x.

Therefore, at the assumed stationary point,

2+3x2−sin⁡x= 0sin⁡x= 3x2+2.\begin{align*} 2+3x^2-\sin x=&\,0\\ \sin x=&\,3x^2+2. \end{align*}

However, x2≥0x^2\geq0, so

3x2+2≥2,3x^2+2\geq2,

whereas sin⁡x≤1\sin x\leq1 for every real xx. This is a contradiction.

Hence the original assumption is false, and the curve has

no stationary points.\boxed{\text{no stationary points}}.

也可以直接给导数设下界;仍使用上面“存在驻点”的反证假设。因为 3x2≥03x^2\geq0 且 sin⁡x≤1\sin x\leq1,

2+3x2−sin⁡x≥2+0−1=1.2+3x^2-\sin x\geq2+0-1=1.

At the assumed stationary point, this contradicts dydx=0\frac{\mathrm{d}y}{\mathrm{d}x}=0. Hence there are no stationary points.