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IAL 2022 Oct Q4

A Level / Edexcel / S1

IAL 2022 Oct Paper · Question 4

题目

Problem

The cumulative distribution function of the discrete random variable WW, which takes only the values 66, 77 and 88, is given by

F(w)=(w+3)(w1)77for w=6,7,8F(w)=\frac{(w+3)(w-1)}{77} \quad\text{for }w=6,7,8

Find E(W)\operatorname{E}(W)

(4)

解答

解法一

思路

展开

这是离散型随机变量的 cumulative distribution function。先用 F(6)F(6)F(7)F(7)F(8)=1F(8)=1 还原每个点的概率,再求期望。

答题过程

展开 F(6)=(6+3)(61)77=4577.\begin{align*} F(6)=\frac{(6+3)(6-1)}{77}=\frac{45}{77}. \end{align*}

So

P(W=6)=4577.\begin{align*} P(W=6)=\frac{45}{77}. \end{align*}

Also,

F(7)=(7+3)(71)77=6077.\begin{align*} F(7)=\frac{(7+3)(7-1)}{77}=\frac{60}{77}. \end{align*}

Therefore

P(W=7)=F(7)F(6)=60774577=1577.\begin{align*} P(W=7)=F(7)-F(6)=\frac{60}{77}-\frac{45}{77}=\frac{15}{77}. \end{align*}

Finally,

P(W=8)=1F(7)=16077=1777.\begin{align*} P(W=8)=1-F(7)=1-\frac{60}{77}=\frac{17}{77}. \end{align*}

Hence

E(W)=64577+71577+81777=51177=7311.\begin{align*} \operatorname{E}(W) =&\,6\cdot\frac{45}{77} +7\cdot\frac{15}{77} +8\cdot\frac{17}{77}\\[3mm] =&\,\frac{511}{77}\\[3mm] =&\,\frac{73}{11}. \end{align*}