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IAL 2025 Jan S2 Q7

A Level / Edexcel / S2

IAL 2025 Jan Paper · Question 7

题目

Problem

A continuous random variable XX has probability density function defined as

f(x)={k(x3)22x60otherwisef(x) = \begin{cases} k(x - 3)^2 & 2 \leqslant x \leqslant 6 \\ 0 & \text{otherwise} \end{cases}

(a) Sketch the graph of y=f(x)y = f(x)

(2)

(b) Hence write down the mode of XX

(1)

(c) Using algebraic integration and showing your working clearly

(i) show that k=328k = \dfrac{3}{28}

(4)

(ii) verify that the upper quartile of XX lies between 5.71 and 5.72

(3)

(Total for Question 7 is 10 marks)

题目中文翻译

连续随机变量 XX 的概率密度函数定义为

f(x)={k(x3)22x60otherwisef(x) = \begin{cases} k(x - 3)^2 & 2 \leqslant x \leqslant 6 \\ 0 & \text{otherwise} \end{cases}

(a) 画出 y=f(x)y = f(x) 的图像。

(b) 由此写出 XX 的众数。

(c) 使用代数积分并清楚地展示你的计算过程

(i) 证明 k=328k = \dfrac{3}{28}

(ii) 验证 XX 的上四分位数在 5.71 和 5.72 之间。

(第 7 题共 10 分)

解答