题目
A company is considering a change to the way it deals with phone calls from its customers. The current average time taken to deal with a phone call is 6 minutes.
A random sample of 50 phone calls that have been dealt with using the current method is taken and the mean of this sample is found to be 6.4 minutes.
The mean deal time for calls dealt with using the current method, measured in minutes, can be modelled by a Normal distribution with standard deviation 1.2 minutes
(a) Carry out a suitable test, at the 5% level of significance, to investigate whether the mean deal time for calls dealt with using the current method is greater than 6 minutes
Give a clear conclusion to this test.
After further investigation the company decides to change the way it deals with phone calls from its customers.
The new deal time for a call, minutes, has probability density function
(b) Find the mode of
(c) Find
(d) Find the median deal time for calls dealt with using the new method.
The new deal time can be modelled by a Normal distribution with mean 4 minutes and standard deviation 0.935 minutes
(e) Using this model, find the probability that it will take more than 18 minutes to deal with 3 randomly selected calls dealt with using the new method.
(Total for Question 6 is 19 marks)
题目中文翻译
一家公司正在考虑改变处理客户电话的方式。当前处理电话的平均时间为 6 分钟。
随机抽取了 50 个使用当前方法处理的电话样本,该样本的平均值为 6.4 分钟。
使用当前方法处理的电话平均处理时间(以分钟为单位)可用标准差为 1.2 分钟的正态分布建模。
(a) 在 5% 的显著性水平下,进行适当的检验来调查使用当前方法处理的电话的平均处理时间是否大于 6 分钟。给出此检验的明确结论。
经过进一步调查后,公司决定改变处理客户电话的方式。
新方法的处理时间 分钟的概率密度函数为
(b) 求 的众数。
(c) 求 。
(d) 求使用新方法处理的电话的中位处理时间。
新方法的处理时间可用均值为 4 分钟、标准差为 0.935 分钟的正态分布建模。
(e) 使用此模型,求随机选择的 3 个使用新方法处理的电话需要超过 18 分钟处理的概率。
(第 6 题共 19 分)