题目
A plant biologist claims that as the percentage moisture content of the soil in a field increases, so does the percentage plant coverage. He splits the field into equal areas labelled A, B, C, D and E and measures the percentage plant coverage and the percentage moisture content for each area. The results are shown in the table below.
| A | B | C | D | E | |
|---|---|---|---|---|---|
| Coverage % | 10 | 12 | 25 | 0 | 6 |
| Moisture % | 30 | 20 | 40 | 10 | 25 |
(a) Calculate Spearman’s rank correlation coefficient for these data.
题目中文翻译
一位植物学家声称,随着田地土壤含水百分比的增加,植物覆盖百分比也会增加。他把这块田地分成大小相等的 A、B、C、D、E 五个区域,并测量每个区域的植物覆盖百分比和土壤含水百分比。结果如下表。
| A | B | C | D | E | |
|---|---|---|---|---|---|
| 覆盖率 % | 10 | 12 | 25 | 0 | 6 |
| 含水率 % | 30 | 20 | 40 | 10 | 25 |
(a) 求这些数据的 Spearman 秩相关系数。
(b) 清楚写出假设,在 5% 显著性水平下检验:这些数据是否支持这位植物学家的说法。
解答
(a)
解法一
思路
展开
分别把植物覆盖率和土壤含水率从大到小排列并赋予名次,再按区域配对。求出名次差 及 后,代入无并列名次时的 Spearman 秩相关系数公式。
答题过程
展开
Ranking both variables from highest to lowest gives
| Area | A | B | C | D | E |
|---|---|---|---|---|---|
| Coverage rank | 3 | 2 | 1 | 5 | 4 |
| Moisture rank | 2 | 4 | 1 | 5 | 3 |
| 1 | 0 | 0 | 1 | ||
| 1 | 4 | 0 | 0 | 1 |
Therefore,
With and no tied ranks,
(b)
解法一
思路
展开
生物学家的主张是含水率越高,覆盖率也越高,即正相关,因此进行单尾 Spearman 秩相关检验。把 (a) 的 与 、 单尾检验的临界值比较。
答题过程
展开
Let be the population rank correlation coefficient between percentage moisture content and percentage plant coverage.
For , the critical value for a one-tailed test at the significance level is .
Since
the test statistic does not lie in the critical region, so is not rejected. There is insufficient evidence at the significance level to support the plant biologist’s claim that percentage plant coverage increases as percentage soil moisture content increases.