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IAL 2026 Jan S3 A Q1

A Level / Edexcel / S3

IAL 2026 Jan A Paper · Question 1

题目

Problem

The table below shows the distance travelled by car and the amount of commission earned by each of 8 salespersons in 2015.

SalespersonDistance travelled (in 1000s of km)Commission earned (in $1000s)
A20.417.7
B22.224.1
C29.920.3
D37.828.3
E25.534.9
F30.229.3
G35.323.6
H16.526.8

(a) Find Spearman’s rank correlation coefficient for these data.

(4)

(b) Stating your hypotheses clearly, test, at the 5% level of significance, whether or not there is evidence of a positive correlation between the distance travelled by car and the amount of commission earned.

(4)
(Total for Question 1 is 8 marks)
题目中文翻译

下表给出了 2015 年 8 名销售人员的汽车行驶距离和所得佣金。

销售人员行驶距离(千公里)所得佣金(千美元)
A20.417.7
B22.224.1
C29.920.3
D37.828.3
E25.534.9
F30.229.3
G35.323.6
H16.526.8

(a) 求这些数据的 Spearman 等级相关系数。

(b) 清楚写出假设,并在 5%5\% 的显著性水平下检验:是否有证据表明汽车行驶距离与所得佣金之间存在正相关。

解答

(a)

解法一

思路

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分别把行驶距离和佣金按同一方向排名,再计算每名销售人员两项排名之差 dd。官方评分资料允许把最大值或最小值定为第 1 名;只要两列采用相同方向,dd 的符号可能改变,但 d2\sum d^2 和最终的 Spearman 等级相关系数不变。

答题过程

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Assigning rank 1 to the largest value gives

SalespersonABCDEFGH
Rank for distance76415328
Rank for commission85731264
dd1-1113-32-244114-444
d2d^211941611616

Therefore,

d2=1+1+9+4+16+1+16+16=64.\sum d^2=1+1+9+4+16+1+16+16=64.

With n=8n=8,

rs=16d2n(n21)=16(64)8(821)=521=0.238(3 s.f.).\begin{align*} r_s=&\,1-\frac{6\sum d^2}{n(n^2-1)}\\ =&\,1-\frac{6(64)}{8(8^2-1)}\\ =&\,\frac{5}{21}\\ =&\,\boxed{0.238}\quad\text{(3 s.f.)}. \end{align*}

Equivalently, assigning rank 1 to the smallest value gives distance ranks

2, 3, 5, 8, 4, 6, 7, 12,\ 3,\ 5,\ 8,\ 4,\ 6,\ 7,\ 1

and commission ranks

1, 4, 2, 6, 8, 7, 3, 5.1,\ 4,\ 2,\ 6,\ 8,\ 7,\ 3,\ 5.

This reverses every rank difference, so d2=64\sum d^2=64 and the same value of rsr_s is obtained.

(b)

解法一

思路

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题目要求检验“正相关”,所以使用单尾检验。把算得的 rsr_sn=8n=85%5\% 单尾检验的临界值 0.64290.6429 比较;由于统计量没有进入临界域,不能拒绝原假设。

答题过程

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Let ρs\rho_s denote the population Spearman rank correlation coefficient.

H0:ρs=0,H1:ρs>0.H_0:\rho_s=0, \qquad H_1:\rho_s>0.

For a one-tailed test with n=8n=8 at the 5%5\% significance level, the critical value is

rs=0.6429,r_s=0.6429,

so the critical region is rs0.6429r_s\geq0.6429.

Since

0.238<0.6429,0.238<0.6429,

the result is not significant and H0H_0 is not rejected. There is insufficient evidence, at the 5%5\% significance level, of a positive correlation between distance travelled and commission earned.